Question 1024522
{{{sec(x)=-4}}}
{{{1/cos(x)=-4}}}
{{{cos(x)=-1/4}}}
You know that,
{{{sin^2(x)+cos^2(x)=1}}}
{{{sin^2(x)+(-1/4)^2=1}}}
{{{sin^2(x)+1/16=1}}}
{{{sin^2(x)=15/16}}}
{{{sin(x)=0 +- sqrt(15)/4}}}
So,
{{{sin(x)=-sqrt(15)/4}}}