Question 1024428
It's very confusing, you didn't use enough parentheses (they're free).
{{{(16n^(1/3)/n)^(-1/4)+2n^(1/6)-n^(1/3)=(16n^(-2/3))^(-1/4)+2n^(1/6)-n^(1/3)}}}
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{{{(16n^(1/3)/n)^(-1/4)+2n^(1/6)-n^(1/3)=(16)^(-1/4)*(n^(-2/3))^(-1/4)+2n^(1/6)-n^(1/3)}}}
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{{{(16n^(1/3)/n)^(-1/4)+2n^(1/6)-n^(1/3)=(1/2)*n^(1/6)+2n^(1/6)-n^(1/3)}}}
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{{{(16n^(1/3)/n)^(-1/4)+2n^(1/6)-n^(1/3)=(5/2)n^(1/6)-n^(1/3)}}}