Question 1024363
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A.
1.  ~(S v E)               Given
2.  (O v M) -> S           Given
3.  ~S & ~E                1, DeMorgan
4.  ~S                     3, Conjunction Elimination
5.  ~(O v M)               4, 2, Modus Tollens
6.  ~O & ~M                5, DeMorgan
7.  Therefore ~M           6, Conjunction Elimination

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Let A = "A student asks one question"
Let B = "A student asks more than one question"
Let C = "A student receives at most one answer"

(A v B) -> C

Get it?
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John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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