Question 1023344
*[illustration fc5.JPG].
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Function is continuous at {{{x=-1}}} and continuous at {{{x=0}}}
{{{lim(x->-1,f(x)=0)}}}
{{{lim(x->0,f(x)=0)}}}
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Derivative is,
{{{dy/dx=x/(2*abs(x)^(3/2))+1}}}
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Derivative is continuous at {{{x=-1}}} and discontinuous at {{{x=0}}}
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