Question 1024262
Take the inverse sin (or arcsin) of both sides
{{{sin(theta) = 1/2}}}
{{{asin(sin(theta)) = asin(1/2)}}}
{{{theta = pi/6}}}  (that's 30 degrees)
But theta also equals
{{{theta = 5pi/6}}}
Then you can add any number of 2 pi to either result...so the complete solution is
theta = pi/6 + 2kpi
theta = 5pi/6 + 2kpi
k being an integer...