Question 1024158
Prove that you can go from the left side and derive the right side or vice versa.
{{{(cos(theta)*sin(theta)+cos(theta))/cos^2(theta)=tan(theta)+sec(theta)}}}
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{{{(cos(theta)(sin(theta)+1))/cos^2(theta)=tan(theta)+sec(theta)}}}
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{{{(sin(theta)+1)/cos(theta)=tan(theta)+sec(theta)}}}
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{{{sin(theta)/cos(theta)+1/cos(theta)=tan(theta)+sec(theta)}}}
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{{{tan(theta)+sec(theta)=tan(theta)+sec(theta)}}}
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True for all values of theta, so the original statement is also true for all values of theta.