Question 1024142
<font face="Times New Roman" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ 3x^2\ +\ 6x\ -\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(a)\ =\ 3a^2\ +\ 6a\ -\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(a\ +\ h)\ =\ 3(a\ +\ h)^2\ +\ 6(a\ +\ h)\ -\ 5\ =\ 3a^2\ +\ 6ah\ +\ 3h^2\ +\ 6a\ +\ 6h\ -\ 5]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{f(a\ +\ h)\ -\ f(a)}{h}\ =\ \frac{3a^2\ +\ 6ah\ +\ 3h^2\ +\ 6a\ +\ 6h\ -\ 5\ -\ 3a^2\ -\ 6a\ +\ 5}{h}\ =\ \frac{6ah\ +\ 3h^2\ +\ 6h}{h}\ =\ 6a\ +\ 3h\ +\ 6]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>