Question 1024187
1.  Re-edit this problem.


2.  log(x+10)  =logx + log10
==> {{{log((x+10)/x) = log10}}}
==> {{{(x+10)/x = 10}}}
==> x+10 = 10x ==> 9x = 10, or x = 10/9.


3.  {{{log(3, log(3,x)) = -1}}}
==> {{{log(3,x) = 3^(-1) = 1/3}}}
==> {{{x = 3^(1/3) = root(3,3)}}}