Question 1024057
2t^2 - 11t = 8
{{{2t^2 - 11t - 8 = 0}}}
The coefficients for the quadratic equation are a = 2 , b = -11 , c = -8
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-(11) +- sqrt( (-11)^2-4*(2)*(-8) ))/(2*2) }}}
First case
{{{x = (-(11) + sqrt( 121+64 ))/4 }}}
{{{x = (-(11) + sqrt( 185 ))/4 }}}
Case two
{{{x = (-(11) - sqrt( 185 ))/4 }}}
Clearly we cannot factor