<PRE><B>Question 1024052</B>
Find the line connecting the center of the circle and the point of intersection. 
The tangent line is perpendicular to this line.
First find the slope,
{{{m=(-5-(-7))/(5-8)=2/(-3)=-2/3}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{(-2/3)*m[2]=-1}}}
{{{m[2]=3/2}}}
Using the point slope form,
{{{y-(-5)=(3/2)(x-5)}}}
{{{y+5=(3/2)x-15/2}}}
{{{y=(3/2)x-15/2-10/2}}}
{{{y=(3/2)x-25/2}}}
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*[illustration fx1.JPG].</PRE>