Question 1024070
Use Cramer's rule,
{{{A=(matrix(3,3,
2,1,1,
3,2,3,
1,4,9
))}}}
{{{abs(A)=-2}}}
.
.
.
{{{A[x]=(matrix(3,3,
1,1,1,
3,2,3,
9,4,9
))}}}
{{{abs(A[x])=-14}}}
.
.
.
{{{A[y]=(matrix(3,3,
2,1,1,
3,3,3,
1,9,9
))}}}
{{{abs(A[y])=18}}}
.
.
.
{{{A[z]=(matrix(3,3,
2,1,1,
3,2,3,
1,4,9
))}}}
{{{abs(A[z])=-14}}}
.
.
.
So then,
{{{x=abs(A[x])/abs(A)=(-14)/(-2)=7}}}
{{{y=abs(A[y])/abs(A)=(18)/(-2)=-9}}}
{{{z=abs(A[z])/abs(A)=(-14)/(-2)=7}}}