Question 88125
graph a cost function rule of:

C(x)=(x^2+6x) / (x+2)
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You have a vertical asymptote at x=-2.
You have x-intercepts at x=0 and at x=-6
As x gets arbitrarily large, C(x) gets arbitrarily large.
AS x approaches -inf, C(x) approaches -inf.
When x=1, C(1) = 7/2
{{{graph(400,300,-10,10,-10,10,(x^2+6x)/(x+2))}}}
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Cheers,
Stan H.