Question 1023940
Using the quotient rule we get
h(x) = (1+e^x) ÷ (1-e^x)
h'(x) = (e^x(1-e^x) - (-e^x)(1+e^x)) / (1 - e^x)^2
h'(x) = ((e^x - e^2x) + (e^x + e^2x)) / (1 - e^x)^2
h'(x) = 2e^x / (1 - e^x)^2