Question 1023845
It may not be obvious but 


{{{log(9,(25))=log(3,(5))}}} 


First {{{X=log(9,(25))}}} 


{{{9^X=25}}}


{{{log9^X=log25}}}


{{{Xlog9=log25}}}


{{{X=log25/log9}}}


{{{X=log5^2/log3^2}}}


{{{X=2log5/2log3}}}


{{{X=log5/log3}}}


{{{X=log(3,(5))}}} 


The rest should flow from this. (the other answer provides the rest of the details)