<PRE><B>Question 12601</B>
Let x = amt of pure antifreeze to be added

You are adding this to 20 gallons of 25% and you will end up a total mixture of x+ 20 at 40%.


The equation is 
.25(20) + x = .40(x+20)
5 + 1.00x = .40x + 8
1.00x - .40x = 8 - 5
.60x = 3


{{{x = 3/.6 = 30/6 = 5 gallons}}}


Does it check?? (It is VERY late in Florida, here!  I don&#39;t guarantee my work or my spelling at this hour!!}}}


R^2 at SCC
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