<PRE><B>Question 1023754</B>
there are 5 consecutive odd nos. difference between the square of average of 1st two and square of average to last two digit is 564 , find the smallest odd no.
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Use n-4, n-2, n, n+2, n+4 as the numbers.
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(n-3)^2 = (n+3)^2 - 564
n^2 - 6x + 9 = n^2 + 6n + 9 - 564
-12n = -564
n = 47
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n-4 = 43
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