Question 1023783
Log(n+2) = 1- Log(n-1)
Log(n+2) + Log(n-1) = 1
log((n+2)*n-1)) = log(10)
n^2 + n - 2 = 10
n^2 + n - 12 = 0
n = -4, n = 3
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n = -4 --> log of negative number, NG