Question 1023782
Solve for n.

log8^(n-3)+log8^(n-1)= 1/2
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log(8^(n-3)) + log(8^(n-1)) = 1/2
log(8^(2n-4)) = 1/2
log(8^(2n-4)) = log(sqrt(10))
8^(2n-4) = sqrt(10)
(2n-4)*log(8) = 1/2
2n-4 = 1/log(64)
2n = 4 + 1/log(64)
n = 2 + 1/log(4096)
n =~ 2.27683