Question 1023773
Use Cramer's rule,
{{{A=(matrix(3,3,
2,-3,-2,
3,-4,3,
4,-5,4
))}}}
{{{abs(A)=-4}}}
.
.
.
{{{A[x]=(matrix(3,3,
10,-3,-2,
8,-4,3,
10,-5,4
))}}}
{{{abs(A[x])=-4}}}
.
.
.
{{{A[y]=(matrix(3,3,
2,10,-2,
3,8,3,
4,10,4
))}}}
{{{abs(A[y])=8}}}
.
.
.
{{{A[z]=(matrix(3,3,
2,-3,10,
3,-4,8,
4,-5,10
))}}}
{{{abs(A[z])=4}}}
.
.
.
{{{x=abs(A[x])/abs(A)=(-4)/(-4)=1}}}
{{{y=abs(A[y])/abs(A)=(8)/(-4)=-2}}}
{{{z=abs(A[z])/abs(A)=(4)/(-4)=-1}}}