Question 1023685
{{{g(x) = x -3}}}, {{{f(x) = x^3 -5x^2 -29x + 105}}} 

First, write the coefficients ONLY inside an upside-down division symbol:

|{{{1}}}... {{{ -5}}} ... {{{-29}}}... {{{ 105}}}
|

Put the test zero, {{{x = 3}}}, at the left,multiply this carry-down value by the test zero, and carry the result up into the next column,add down the column:

{{{3}}}|{{{1}}}... {{{-5}}}...... {{{ -29}}}..... {{{ 105}}}
...|...........{{{3}}}......{{{-6}}}..........{{{-105}}}
---------------------------------
...|{{{1}}}......{{{-2}}}....{{{-35}}}.........{{{0}}}


{{{(x^3-5x^2 -29x + 105)/(x-3)=x^2-2x-35}}}