Question 1023654
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 Five boys weighed themselves in pairs in all possible combinations. The measured  weights were 90kg, 92kg, 93kg, 94kg, 95kg, 96kg, 97kg, 98kg, 100kg and 101kg.  The total weight of the five boys is what?
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A + B = 90,
A + C = 92,
A + D = 93,
A + E = 94,
B + c = 95,
B + D = 96,
B + E = 97,
C + D = 98,
C + E = 100,
D + E = 101.

Now add all these equations (left sides and right sides). You will get

4*(A + B + C + D + E) = the sum (calculate this sum yourself please).

Now A + B + C + D + E = {{{the_sum/4}}}.

It is your answer.
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