<PRE><B>Question 1023516</B>
With my calculator, I get {{{ arctan( 1.6852 ) = 59.315 }}} degrees
Because {{{ tan( 59.315 ) = 1.6852 }}}, I can eliminate 
the 2nd and 4th quadrants where the tan is negative.
--------------------
In the first quadrant, I just have {{{ 59.315 }}} degrees
In the 3rd quadrant, I have {{{ 180 + 59.315 = 239.315 }}} degrees
--------------------
Note that in the 1st quadrant, the signs are +/+
and in the 2nd quadrant, the signs are -/-
Both give me a sign of +</PRE>