Question 1023415
3b*pi+14=12a*pi+7a
<pre>
The terms which are irrational multiples of pi on each side 
must be equal:

3b*pi=12a*pi

The terms which are integers on each side must be equal:

14 = 7a

{{{system(3b*pi=12a*pi,14=7a)}}}

Divide the first equation through by 3<font face="symbol">p</font>.
Divide the second equation through by 7:

{{{system(b=4a,2=a)}}}

Substitute 2 for "a" in b=4a

b=4(2)
b=8

a+b = 2+8 = 10

Edwin</pre>