Question 1023352
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Write the polar equation r^2 - 2r cos(theta) = 0 in rectangular form.
x^2 + y^2 - 2y = 0
y = 2x
x + y - 2 = 0
x^2 + y^2 - 2x = 0
Any help will be much appreciated!
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1.  {{{r^2}}} = {{{x^2 + y^2}}}.

2.  r*cos(theta) = x.


3.  Therefore, the polar equation  {{{r^2 - 2r*cos(theta)}}} = {{{0}}}  in rectangular form is

    {{{x^2 + y^2 - 2x}}} = {{{0}}}.


That's all.

It is your answer.
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