Question 1023340
{{{N+sqrt(N)=7/36}}}
Substituting,
{{{x=sqrt(N)}}}
{{{x^2=N}}}}
So then,
{{{x^2+x-7/36=0}}}
{{{36x^2+36x-7=0}}}
{{{(6x-1)(6x+7)=0}}}
Only solve for the positive value,
{{{6x-1=0}}}
{{{6x=1}}}
{{{x=1/6}}}
{{{sqrt(N)=1/6}}}
{{{N=1/36}}}