Question 1023320
Solve one equation for a variable and substitute this into the other equation and solve for that variable.



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Good!
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A simple way, not the only way, is {{{y=3-2x}}}, and then,
{{{4x-3(3-2x)=5}}}
{{{4x-9+6x=5}}}
{{{10x-9=5}}}
{{{10x=5+9}}}
{{{10x=14}}}
{{{x=14/10}}}
{{{x=7/5}}}-------one variable done.
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Go back to first formula for y.
{{{y=3-2x}}}
{{{y=3-2(7/5)}}}
{{{y=15/5-14/5}}}
{{{y=1/5}}}---------the other variable, done.