Question 1023225
The number of days in a period of four consecutive calendar years where one year is a leap year is the integer number
{{{365*3+366=1461}}} ,
which we can express as {{{1461.0000}}} to the nearest ten-thousandth,
because {{{1/10000=0.0001}}} is one ten-thousandth. 
The number of days in four orbits of Earth is the non-integer number
{{{4*365.2422=1460.9688}}} .
 
The difference is
{{{1461.0000-1460.9688=highlight(0.0312)}}} .
 
NOTES:
1) The length of the tropical year changes a little over the centuries, but for now {{{365.24220}}} is a good approximation.
(I did not know that before your question, so thank you for the learning opportunity).
Since {{{365.24220}}} is a good approximation,
 we do not have to worry about {{{365.2422}}} , given with 4 decimal places,
not being precise enough to make {{{1460.9688}}} not being {{{4*365.24220}}} to the nearest {{{1/1000}}} .
 
2) Calendar years are leap years if divisible by {{{4}}}, but not by {{{100}}} unless divisible  by {{{400}}} ,
so in {{{400}}} years there are {{{97}}} leap years,
and the average length of a calendar year is {{{365&97/400=365.2425}}} .
(I was taught that in the 9th grade, and it stuck with me).