Question 1023218
1)  The value of the determinant would be 0, because of the presence of a column of zeros.

2)  The first column was multiplied by 2 (elementary row operation of the second type), hence the value of the determinant would be 2*9 = 18.

3)  The new second row was obtained by multiplying the 3rd row by 1 and adding it to the old second row.  Any elementary row operation of the 3rd type doesn't change the value of the determinant, hence the determinant is still 9.