Question 1014821
<pre>

{{{(x^5+32)/(x+2)}}}

We write the numerator as

{{{1x^5+0x^4+0x^3+0x^2+0x+32}}}

and change the sign of 2 in x+2 and use -2

-2 | 1   0   0   0   0  32
   |<u>    -2   4  -8  16 -32</u> 
     1  -2   4  -8  16   0

We interpret the bottom line as coefficients
of a polynomial which is one degree less than
the original.  So it will have degree 4

The quotient is

{{{(x^5+32)/(x+2)}}}{{{""=""}}}{{{1x^4-2x^3+4x^2-8x+16}}}

erase the 1 coefficient

{{{(x^5+32)/(x+2)}}}{{{""=""}}}{{{x^4-2x^3+4x^2-8x+16}}}

Edwin</pre>