Question 1023188
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Evaluate y' at the point (2,1) if  x2 y3 = x + y + 1
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2xy^3 + 3x^2y^2y' = 1 + y'


4 + 12y' = 1 + y'


11y' = -3


y' = {{{-3/11}}}.


You did it correctly.
I only wrote the answer.