Question 1023131
i presume you mean exponentiation, which is modeled using the exponentiation symbol of ^.


based on that, x = (y+2)2 would be modeled as x = (y+2)^2.


assuming that's what you meant, then you would take the square root of both sides of the equation to get plus or minus sqrt(x) = y+2.


you would then subtract 2 from both sides of the equation to get plus or minus sqrt(x) - 2 = y.


this can also be shown as y = - 2 plus or minus sqrt(x).


to confirm that this is the equivalent of the original equation, then do the following:


start with y = -2 plus or minus sqrt(x).


add 2 to both sides of this equation to get y + 2 = plus or minus sqrt(xj).


square both sides of this equation to get (y+2)^2 = (sqrt(x))^2 or (-sqrt(x))^2.


in either case, you get (y+2)^2 = x.


when you deal with square roots, the following rules apply.


if the problem states that y^2 = 4, then the solution is y = plus or minus 2.


is the problem states that y = sqrt(4), then the solution is y = 2, not plus or minus 2.


it's a subtle difference that can be difficult to understand.


here's a reference that discusses it.


<a href = "https://www.mathsisfun.com/algebra/square-root.html" target = "_blank">https://www.mathsisfun.com/algebra/square-root.html</a>