Question 1023039
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If *[tex \Large \alpha] is a zero of a polynomial function, then *[tex \Large x\ -\ \alpha] is a factor of the polynomial.  If *[tex \Large a\ +\ bi] is a zero of a polynomial function with rational coefficients, then its conjugate, *[tex \Large a\ -\ bi] is also a zero of the polynomial.


Your problem is written ambiguously. Are the given zeros 16, 8, and *[tex \Large 2\ +\ i] or is 16 the problem number?  I can't help you unless you are clear about what you write.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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