Question 1023025
On 1), when you FOIL you have to end up with x^2+8x-12=0. But this number is irreducible. The most you can do is x(x+8) = 12 or x(x+8)-12 = 0 etc. which is how you have it on your second answer. However, since it's irreducible I don't see a way to write it as an ordered pair. Maybe I'm missing something.
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5x^2+19x-35 = 0
x^2+(19x)/5-7 = 0
x^2+(19 x)/5 = 7
x^2+(19 x)/5+361/100 = 1061/100
(x+19/10)^2 = 1061/100
x+19/10 = sqrt(1061)/10 or x+19/10 = -sqrt(1061)/10
Subtract 19/10 from both sides:
x = sqrt(1061)/10-19/10 or x+19/10 = -sqrt(1061)/10
x = sqrt(1061)/10-19/10 or x = -19/10-sqrt(1061)/10
Note: When you went from 5x(x+19)=35 to x+19=35/5 you ignored an x and the fact that 19x also has to be divided by 5, in other words, you would have:x(x+19)/5= 7 which is what I have (I have x^2(19x)/5 = 7).
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-6x^2-x+5= 0 Finally, something to work with!!
-(x+1) (6 x-5) = 0
Suerte en tus estudios.
J