Question 1022868
 Log(x+1) = 2logx
exponent equiv
 {{{log((x+1))=log((x^2))}}}
therefore
x + 1 = x^2
A quadratic equation 
0 = x^2 - x - 1
use the quadratic formula a=1; b=-1; c-1
Two solutions
x = -.618
x = 1.618, only solution in the original equation