Question 1022958
Three times the tens digit of a certain 2 digit number is 2 more than four times the units digit. The difference between the given number and the number obtained by reversing the digits is two less than twice the sum of the digits. Find the number?
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Let the number be 10t + u
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Equations:
3t = 4u+2
10t+u-(10u+t) = 2(t+u)-2
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Rearrange::
3t - 4u = 2
9t - 9u = 2t+2u-2
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3t-4u = 2
7t - 11u = -2
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Modify for elimination::
21t - 28u = 14
21t - 33u = -6
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Subtract and solve for "u"::
5u = 20
u = 4
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Solve for "t"::
3t - 4u = 2
3t - 16 = 2
3t = 18
t = 6
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Ans:: 10t+u = 64
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Cheers,
Stan H.
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