Question 1022943
{{{3x^2-2x+1}}} 

{{{3(x^2-(2/3)x)+1}}}.....complete square

{{{3(x^2-(2/3)x+b^2)-3b^2+1}}}-> since coefficient {{{a=1}} and {{{2ab= (2/3)}}}, we have {{{2*1b= (2/3)}}}->{{{b= (2/3)/2}}}->{{{b= 2/6}}}->{{{b= 1/3}}}

so, we have
{{{3(x^2-(2/3)x+(1/3)^2)-3*(1/3)^2+1}}}

{{{3(x-1/3)^2-3/9+1}}}

{{{3(x-1/3)^2-1/3+3/3}}}

{{{3(x-1/3)^2+2/3}}}