Question 1022311
For n = 1: {{{2^1 > 1}}}, which is true

Assume for n = k>1 that {{{2^k > k}}}.

Show that the hypothesis is true also for n = k + 1, or that {{{2^(k+1) >k+1}}}.

But {{{2^(k+1) = 2^k*2 >2k = k+k>k+1}}}, and the statement is proved.