Question 1022751
 if 30 is added to a certain number
n + 30
 and the sum is divided by 6,
{{{((n+30))/6}}}
 the result is 1 more than 1/2 of the original number.
{{{((n+30))/6}}} = {{{1/2}}}n + 1
Multiply by 6 and cancel the denominators
n + 30 = 3n + 6
n - 3n = 6 - 30
-2n = -24
n = -24/-2
n = +12 is the number
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Check solution in orignal equation
{{{((12+3))/6}}} = {{{1/2}}}(12) + 1
{{{((42))/6}}} = 6 + 1