Question 1022772
If something decays according to the equation y=ae^-0.0974t, where t- is in days.  After 15 days, 20 grams of the compound remain. What was the original amount of the compound?
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a = amount 15 days earlier.
y = amount now
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y = a*e^(-0.0974*15) = 20
a = 20/e^(-0.0974*15)
a =~ 86.205 grams