Question 1022728
at time 0, the height is 2.5m
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With a diameter of 50.5 meters, the wheel has a radius of 25.25 meters.  The height will oscillate with amplitude of 25.25 meters above and below the center.
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Riders board 2.5 meters above ground level, so the center of the wheel must be located 25.25 + 2.5 = 27.75 meters above ground level.  The midline of the oscillation will be at 27.75 meters.
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The wheel takes 2 minutes to complete 1 revolution, so the height will oscillate with period of 2 minutes.
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Lastly, since the rider boards at the lowest point, the height will start at the smallest value and increase, following the shape of a flipped cosine curve.
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The equation for the rider's height will be
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h(t) = -25.25cos(pi*t) + 27.75
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