Question 1022701
let the side of the square playing field be called x.


the area of the square playing field is equal to side * side which is equal to side squared which is equal to x^2.


since it is square, the length and the width are both equal to x.


add 2 meters to the length and you get a length of x + 2.


subtract 2 meters from the width to get a width of x - 2.


the area of the rectangular playing field is equal to length * width which is equal to (x + 2) * (x-2) which is equal to x^2 - 4.


the area of the square playing field is greater than the area of the rectangular playing field by 4 meters.


x^2 minus (x^2 - 4) = x^2 - x^2 + 4 = 4.


the difference in the area will always be 4 meters, regardless of the value of x.