Question 1022663
{{{y^2=100-x^2}}}
{{{y=0+- sqrt(100-x^2)}}}


{{{dy/dx=0+- (1/2)(100-x^2)^(-1/2)*(-2x)}}}


{{{dy/dx=0+- (1/2)(2x)/sqrt(100-x^2)}}}


{{{dy/dx=0+- x/sqrt(100-x^2)}}}


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{{{x/sqrt(100-x^2)=3/4}}}


{{{x^2/(100-x^2)=9/16}}}


{{{16x^2=9(100-x^2)}}}


{{{16x^2=900-9x^2}}}


{{{25x^2=900}}}


{{{5x=0+- 30}}}


{{{highlight(x=0+- 6)}}}, and you can find the corresponding y coordinate for each.