Question 1022590
Call the rate of the wind, w.
Since rate times time equals distance, we can write
396 = (170+w)t and
324 = (170-w)t
Now solve for t and set them equal...we get
{{{396/(170+w) = 324/(170-w)}}}
Then cross multiply and solve for w...
396(170-w) = 324(170+w)
67320 - 396w = 55080 + 324w
12240 = 720w
w = 17 mph