Question 1022583
To evaluate this, we multiply top and bottom by the conjugate of the denominator...so we have
{{{(4+2i)/(3-i) = ((4+2i)/(3-i))((3+i)/(3+i)) = (10 + 2i)/10 = (5 + i)/5}}}
or 
{{{1 + (1/5)i}}}