Question 1022574
Solving for t, we get from
{{{R = R[0](1 + at)}}}
{{{R/R[0] = 1 + at}}}
{{{(R/R[0]) - 1 = at}}}
and
{{{(R/R[0] - 1)/a = t}}}
or
{{{t = (R/(aR[0])) - 1/a}}}