Question 87932
{{{f(x) = (-2/5)(x + 2)^2 - 3}}}
This is in quadratic form: {{{f(x) = a(x - h)^2 + k}}}
* "a" determines if the parabola opens up or down
~> positive "a" means up
~> negative "a" means down
* "h" and "k" determines the vertex
Vertex (h,k)
{{{f(x) = (-2/5)(x + 2)^2 - 3}}}
a = -2/5
h = -2
k = -3
Vertex: (-2,-3)
Opens downward
The axis of symmetry is {{{x = -2}}} since the parabola is vertical.
{{{graph(300,300,-6,1,-8,1,(-2/5)(x + 2)^2 - 3)}}}