Question 1022322
Addition of the two vectors; that of the plane and that of the wind.


(400*cos(90),400*sin(90))+(50*cos(0),50*sin(0))


( 400*cos(90)+50*cos(0), 400*sin(90)+50*sin(0) )


(0+50, 400+0)


( 50, 400 )


You can use this to find the angle, and to find the size of the rate.



Size of the rate, or speed, is  {{{sqrt(50^2+400^2)}}};
and the angle is  {{{tan(40/5)=tan(8)}}}, meaning {{{arctan(8)}}}.
83.9 degrees North of Eastward.