Question 1022348
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If


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ PV^{1.4}\ =\ C]


then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V^{1.4}\ =\ \frac{C}{P}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln\left(V^{1.4}\right)\ =\ \ln\left(\frac{C}{P}\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 1.4\,\cdot\,\ln\left(V\right)\ =\ \ln\left(\frac{C}{P}\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln\left(V\right)\ =\ \frac{\ln\left(\frac{C}{P}\right)}{1.4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V\ =\ e^{\frac{\ln\left(\frac{C}{P}\right)}{1.4}}]


Plug in the numbers an do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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