Question 1022318

Solve: 7e^3x + 5 = 40
* round to the nearest thousandth
* only algebraic solution will be accepted
<pre>{{{7e^(3x) + 5 = 40}}}
{{{7e^(3x) = 40 - 5}}}
{{{7e^(3x) = 35}}}
{{{e^(3x) = 35/7}}}
{{{e^(3x) = 5}}}
ln 5 = 3x
{{{x = (ln (5))/3}}}, or {{{highlight_green(0.536)}}}