Question 1022398
<pre>
You must be very accurate when you solve a system of equations
by graphing. You must use graph paper with large squares and 
use a ruler.

Make a table of points for each line:

 x | y      x | y
 1 | 0      1 |-2 
 3 |-1      3 | 2
-1 | 1     -1 |-6


Plot those points and draw lines through them, using
graph paper and a ruler:

{{{drawing(500,500,-6,6,-7,5,

circle(1,0,0.15),circle(1,0,0.13),circle(1,0,0.11),circle(1,0,0.09),circle(1,0,0.07),circle(1,0,0.05),circle(1,0,0.03),circle(1,0,0.01),

circle(3,-1,0.15),circle(3,-1,0.13),circle(3,-1,0.11),circle(3,-1,0.09),circle(3,-1,0.07),circle(3,-1,0.05),circle(3,-1,0.03),circle(3,-1,0.01),

circle(-1,1,0.15),circle(-1,1,0.13),circle(-1,1,0.11),circle(-1,1,0.09),circle(-1,1,0.07),circle(-1,1,0.05),circle(-1,1,0.03),circle(-1,1,0.01),

circle(1,-2,0.15),circle(1,-2,0.13),circle(1,-2,0.11),circle(1,-2,0.09),circle(1,-2,0.07),circle(1,-2,0.05),circle(1,-2,0.03),circle(1,-2,0.01),

circle(3,2,0.15),circle(3,2,0.13),circle(3,2,0.11),circle(3,2,0.09),circle(3,2,0.07),circle(3,2,0.05),circle(3,2,0.03),circle(3,2,0.01),

circle(-1,-6,0.15),circle(-1,-6,0.13),circle(-1,-6,0.11),circle(-1,-6,0.09),circle(-1,-6,0.07),circle(-1,-6,0.05),circle(-1,-6,0.03),circle(-1,-6,0.01),


 line(-11,6,9,-4), line(-9,-22,10,16),grid(1) )}}}

So you see the lines cross at a point that has fractions for both
coordinates.  It's a good idea to draw a vertical and a horizontal
line (in red below) to the x and y-axis, like this:

{{{drawing(500,500,-6,6,-7,5,
red(line(1.8,-.4,0,-.4), line(1.8,-.4,1.8,0)),
circle(1,0,0.15),circle(1,0,0.13),circle(1,0,0.11),circle(1,0,0.09),circle(1,0,0.07),circle(1,0,0.05),circle(1,0,0.03),circle(1,0,0.01),

circle(3,-1,0.15),circle(3,-1,0.13),circle(3,-1,0.11),circle(3,-1,0.09),circle(3,-1,0.07),circle(3,-1,0.05),circle(3,-1,0.03),circle(3,-1,0.01),

circle(-1,1,0.15),circle(-1,1,0.13),circle(-1,1,0.11),circle(-1,1,0.09),circle(-1,1,0.07),circle(-1,1,0.05),circle(-1,1,0.03),circle(-1,1,0.01),

circle(1,-2,0.15),circle(1,-2,0.13),circle(1,-2,0.11),circle(1,-2,0.09),circle(1,-2,0.07),circle(1,-2,0.05),circle(1,-2,0.03),circle(1,-2,0.01),

circle(3,2,0.15),circle(3,2,0.13),circle(3,2,0.11),circle(3,2,0.09),circle(3,2,0.07),circle(3,2,0.05),circle(3,2,0.03),circle(3,2,0.01),

circle(-1,-6,0.15),circle(-1,-6,0.13),circle(-1,-6,0.11),circle(-1,-6,0.09),circle(-1,-6,0.07),circle(-1,-6,0.05),circle(-1,-6,0.03),circle(-1,-6,0.01),

 line(-11,6,9,-4), line(-9,-22,10,16),grid(1) )}}}
 

It looks like the x coordinate is a little less than 2,
but not close enough to be 1.9, so I'd guess x = 1.8.
The y coordinate is a little less than halfway to -1,
which would be -0.5, but closer to -0.5 than the other 
was to 2, so I'd guess that it is y = -0.4

That's the best you can do with graphing.

Edwin</pre>